doran6

01-12-2010, 05:35 PM

hello i copied a question on nov 2009

(1.1414 xoffset) -2 (.414x (clr) centre line radius this is the formula

example degree of elbow: 60=.577

45=.414

30=2.00???????????is.268

example in your situation

45 degree elbow 48x20

(1.414x36 offset)-2(.414x72)

=21.288 thats the length of the duct in between your on your two 45 degree elbow...

my question is: let's say the 48*20 offset of 36" got to fit in 75" space

it might fit for all degree 30,45,60 with any kind of radius

but if i pick 45º and clr and if fit within 75" : i want to know the diaganal lenght between offset plus know the straight at one end to reach 75"

plus even more challenge: have a formula to find the exact degree elbow & clr (ex. 55º & 112"clr)with no straight in between if possible in that case

i've been trying to find that formula for many years

hope you understand my question

thanks

doran6

sheetmetal worker, ottawa, ontario

[/b][/i]

(1.1414 xoffset) -2 (.414x (clr) centre line radius this is the formula

example degree of elbow: 60=.577

45=.414

30=2.00???????????is.268

example in your situation

45 degree elbow 48x20

(1.414x36 offset)-2(.414x72)

=21.288 thats the length of the duct in between your on your two 45 degree elbow...

my question is: let's say the 48*20 offset of 36" got to fit in 75" space

it might fit for all degree 30,45,60 with any kind of radius

but if i pick 45º and clr and if fit within 75" : i want to know the diaganal lenght between offset plus know the straight at one end to reach 75"

plus even more challenge: have a formula to find the exact degree elbow & clr (ex. 55º & 112"clr)with no straight in between if possible in that case

i've been trying to find that formula for many years

hope you understand my question

thanks

doran6

sheetmetal worker, ottawa, ontario

[/b][/i]